SQL
Q43.
Database table by name Loan_Records is given below. What is the output of the following SQL query? SELECT count(*) FROM( (SELECT Borrower. Bank_Manager FROM Loan_Records) AS S NATURAL JOIN (SELECT Bank_Manager, Loan_Amount FROM Loan_Records) AS T);Q44.
Consider the following relational schema:Student(school-id,sch-roll-no,sname,saddress) School(school-id,sch-name,sch-address,sch-phone) Enrolment(school-id,sch-roll-no,erollno,examname) ExamResult(erollno,examname,marks) What does the following SQL query output?SELECT sch-name, COUNT (*) FROM School C, Enrolment E, ExamResult R WHERE E.school-id = C.school-id AND E.examname = R.examname AND E.erollno = R.erollno AND R.marks = 100 AND S.school-id IN (SELECT school-id FROM student GROUP BY school-id HAVING COUNT (*) > 200) GROUP By school-idQ45.
Consider the following schema:Emp (Empcode, Name, Sex, Salary, Deptt)A simple SQL query is executed as follows: SELECT Deptt FROM Emp GROUP by Dept Having avg (Salary) > {select avg (Salary) from Emp}The output will be